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Pankaj Gupta
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Pankaj GuptaScholar
Asked: 14 hours agoIn: Information Technology

What will be the output of substring(0,0) in java?

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What will be the output of substring(0,0) in java?

What will be the output of substring(0,0) in java?

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0)0) in javasubstringsubstring(0
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  1. Pankaj Gupta
    Pankaj Gupta Scholar
    Added an answer about 14 hours ago

    In Java, the substring(int beginIndex, int endIndex) method returns a new string starting from beginIndex (inclusive) and ending at endIndex (exclusive). Example: String str = "example"; System.out.println(str.substring(0, 0)); Output: "" This means an empty string is returned. Explanation: beginIndRead more

    In Java, the substring(int beginIndex, int endIndex) method returns a new string starting from beginIndex (inclusive) and ending at endIndex (exclusive).

    Example:

    String str = “example”;
    System.out.println(str.substring(0, 0));

    Output: “”
    This means an empty string is returned.

    Explanation:

    beginIndex = 0 (inclusive)

    endIndex = 0 (exclusive)

    No characters are selected, so the result is an empty string “”.

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Pankaj Gupta
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Pankaj GuptaScholar
Asked: 3 weeks agoIn: Information Technology

What is the difference between whitespace and unicode space character.

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What is the difference between whitespace and unicode space character.

What is the difference between whitespace and unicode space character.

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javaunicode spacewhitespace
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  1. Pankaj Gupta
    Pankaj Gupta Scholar
    Added an answer about 3 weeks ago

    Key Difference Term Whitespace Unicode Space Character Definition Any character that creates "blank" space in text (invisible characters that separate words or lines). Specific space-like characters defined in the Unicode standard. Scope A broad category that includes a variety of invisible characteRead more

    Key Difference

    Term Whitespace Unicode Space Character

    Definition Any character that creates “blank” space in text (invisible characters that separate words or lines). Specific space-like characters defined in the Unicode standard.
    Scope A broad category that includes a variety of invisible characters like spaces, tabs, and newlines. A subset of Unicode characters that are defined as various types of space.
    Examples ‘ ‘ (space), \n (newline), \t (tab), \r (carriage return) U+0020 (Space), U+00A0 (No-Break Space), U+2003 (Em Space), U+2009 (Thin Space), etc.
    In Java / Programming Identified by Character.isWhitespace() Each Unicode space has a specific code point, width, and behavior in rendering.

    1. Whitespace Characters

    These are general characters that create space but are often interpreted by programming languages or parsers.

    In Java, Character.isWhitespace(c) returns true for:

    Standard space ‘ ‘ (U+0020)

    Tab \t (U+0009)

    Newline \n (U+000A)

    Carriage return \r (U+000D)

    Vertical tab \u000B

    Form feed \u000C

    All Unicode characters categorized as whitespace.

    2. Unicode Space Characters

    Unicode defines many space characters explicitly, each with a specific purpose or width. Here are a few notable ones:

    Unicode Name Width/Use

    U+0020 Space Standard space character
    U+00A0 No-Break Space Same as space but prevents line breaks
    U+2000 En Quad Space equal to 1 en
    U+2001 Em Quad Space equal to 1 em
    U+2002 En Space Narrower than em space
    U+2003 Em Space Wider space for typesetting
    U+2009 Thin Space Very narrow space
    U+202F Narrow No-Break Space Narrower than no-break space
    U+3000 Ideographic Space Used in East Asian scripts, full-width

    These characters may not be detected by simple string manipulations unless Unicode-aware methods are used.

    Important Distinctions

    All Unicode space characters are whitespace, but not all whitespace characters are Unicode space characters.

    Some whitespace characters (like \n, \t) are control characters, not printable spaces.

    Unicode spaces may have width, non-breaking behavior, or typographic purpose.

    Summary

    Concept Includes

    Whitespace Spaces, tabs, newlines, form feeds, etc.
    Unicode Space Characters Precisely defined space characters like U+00A0, U+2002, U+2003, etc.

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Aditya Gupta
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Aditya GuptaScholar
Asked: 4 weeks agoIn: Politics & Political Science

India’s upcoming census (by March 2027) will include caste for …

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India’s upcoming census (by March 2027) will include caste for the first time since 1951. Will this help improve social justice and policy targeting, or risk reinforcing caste divisions? 

  • India’s upcoming census (by March 2027) will include caste for the first time since 1951. Will this help improve social justice and policy targeting, or risk reinforcing caste divisions? 
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Pankaj Gupta
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Pankaj GuptaScholar
Asked: 4 weeks agoIn: Health & Fitness

What is primary amebic meningoencephalitis ?

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What is primary amebic meningoencephalitis ?

What is primary amebic meningoencephalitis ?

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dieseaseprimary amebic meningoencephalitis
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  1. Pankaj Gupta
    Pankaj Gupta Scholar
    Added an answer about 4 weeks ago

    Primary amebic meningoencephalitis (PAM) is a rare, usually fatal brain infection caused by the amoeba Naegleria fowleri. This free-living amoeba is commonly found in warm freshwater environments like lakes, rivers, and hot springs, as well as in poorly maintained pools or contaminated water supplieRead more

    Primary amebic meningoencephalitis (PAM) is a rare, usually fatal brain infection caused by the amoeba Naegleria fowleri. This free-living amoeba is commonly found in warm freshwater environments like lakes, rivers, and hot springs, as well as in poorly maintained pools or contaminated water supplies.

    PAM occurs when the amoeba enters the body through the nose, typically during activities like swimming or diving. From there, it travels to the brain, causing severe inflammation of the brain and its surrounding membranes (meningoencephalitis). Symptoms usually start within 1–9 days and include headache, fever, nausea, vomiting, stiff neck, confusion, seizures, and coma. The infection progresses rapidly, often leading to death within days if untreated.

    Diagnosis is challenging and typically involves detecting the amoeba in cerebrospinal fluid or brain tissue, often confirmed posthumously. Treatment is difficult due to the rapid progression and limited effective drugs, but regimens may include antifungal and antimicrobial agents like amphotericin B, miltefosine, and others, with supportive care. Survival is rare, with only a few documented cases globally.

    Prevention focuses on avoiding exposure: using nose clips while swimming in warm freshwater, ensuring proper pool maintenance, and avoiding untreated water for nasal irrigation. The CDC and WHO emphasize that PAM is not contagious and cannot be contracted from drinking contaminated water.

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Harpreet
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HarpreetBeginner
Asked: 1 month agoIn: Environment

How does the classification of organisms contribute to our understanding …

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How does the classification of organisms contribute to our understanding of biodiversity and influence conservation strategies?

How does the classification of organisms contribute to our understanding of biodiversity and influence conservation strategies?

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biodiversityenvironment
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  1. Pankaj Gupta
    Pankaj Gupta Scholar
    Added an answer about 1 month ago

    The classification of organisms, also known as taxonomy, plays a foundational role in biology and conservation science. It is much more than a naming system—it is a lens through which we understand the complexity, relationships, and evolutionary history of life on Earth. Here’s how it significantlyRead more

    The classification of organisms, also known as taxonomy, plays a foundational role in biology and conservation science. It is much more than a naming system—it is a lens through which we understand the complexity, relationships, and evolutionary history of life on Earth. Here’s how it significantly contributes to our understanding of biodiversity and shapes conservation strategies:

    1. Bringing Order to Biodiversity

    Earth is home to millions of species, many of which are yet to be discovered. Classification helps organize this vast biological diversity into a structured system—kingdom, phylum, class, order, family, genus, and species. By doing so, scientists can make sense of the natural world, identify patterns in evolution, and detect biodiversity hotspots that need protection.

    2. Revealing Evolutionary Relationships

    Through phylogenetics and taxonomy, organisms are grouped based on shared characteristics and genetic lineage. This reveals how species are related and how they’ve evolved over time. Understanding these relationships helps conservationists prioritize the protection of entire lineages, not just individual species, thereby preserving evolutionary heritage.

    3. Identifying Keystone and Indicator Species

    Classification helps in recognizing keystone species—those that have a disproportionately large effect on their environment. Similarly, it identifies indicator species, which reflect the health of an ecosystem. Protecting such species, once correctly classified, leads to the conservation of entire ecological communities.

    4. Enhancing Global Collaboration

    A universally accepted classification system allows scientists across the world to communicate unambiguously. This consistency is critical in global conservation efforts, such as those led by the IUCN (International Union for Conservation of Nature), CITES, and the Convention on Biological Diversity.

    5. Informing Legal and Policy Frameworks

    Accurate classification enables governments and conservation agencies to draft species-specific protection laws. For example, endangered species lists are built on precise taxonomic data. Misclassification can lead to conservation efforts being misdirected or overlooked altogether.

    6. Guiding Resource Allocation

    Conservation resources are limited. Classification helps identify species at risk of extinction, prioritize those with small populations or restricted ranges, and allocate funding to projects with the greatest potential impact.

    7. Facilitating Biodiversity Monitoring

    Monitoring biodiversity over time requires a clear understanding of which species exist in a region. Classification provides this baseline. It also enables the detection of invasive species and the assessment of how climate change or habitat loss is affecting various taxonomic groups.

    Conclusion

    In essence, classification is the backbone of biodiversity science. It allows us not only to catalog life but also to understand the intricate web of relationships among species. This understanding is crucial for designing effective conservation strategies that are informed, targeted, and globally coordinated. Without classification, biodiversity would remain an overwhelming and unmanageable concept—limiting our ability to protect it.

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Pankaj Gupta
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Pankaj GuptaScholar
Asked: 1 month agoIn: Food and Cooking

What makes Robusta coffee stand out from the rest?

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What makes Robusta coffee stand out from the rest?

What makes Robusta coffee stand out from the rest?

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coffeerobusta
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  1. AVG
    AVG Explorer
    Added an answer about 1 month ago

    Robusta Coffee: The Underdog Brewing a Bold Comeback Robusta coffee, sourced from the Coffea canephora plant, has long been regarded as the less refined sibling of Arabica. But in recent years, this sturdy bean has been gaining newfound respect in both coffee-growing and coffee-drinking communitiesRead more

    Robusta Coffee: The Underdog Brewing a Bold Comeback

    Robusta coffee, sourced from the Coffea canephora plant, has long been regarded as the less refined sibling of Arabica. But in recent years, this sturdy bean has been gaining newfound respect in both coffee-growing and coffee-drinking communities around the world. So, what’s driving the buzz around Robusta?

    A Crop Built for the Future

    Robusta plants are notably resilient. They grow well in lower altitudes and warmer climates, can tolerate harsher conditions, and are naturally more resistant to pests and diseases. This durability translates to higher yields and greater crop reliability, which is becoming increasingly important in a world grappling with climate change and unpredictable weather patterns.

    A Bold, Caffeinated Kick

    Robusta beans pack nearly twice the caffeine of Arabica beans. This gives the coffee a strong, bold flavor—often described as earthy, woody, or nutty, with a characteristic bitterness. While Arabica is praised for its sweetness and complexity, Robusta offers a potent energy boost and a punchy profile that some coffee lovers find irresistible, especially in espresso blends and traditional coffee preparations.

    Affordability and Efficiency

    From an economic standpoint, Robusta is more cost-effective to cultivate. It requires less intensive care, fewer chemical treatments, and yields more beans per plant. These advantages make it an attractive option for farmers, especially in developing regions where resources are limited. Its lower market price also allows it to be used widely in instant coffee and commercial blends, making it a staple in households across the globe.

    Sustainability and Climate Resilience

    Because Robusta thrives in environments where Arabica struggles, it plays a critical role in sustaining global coffee supplies. It can grow in areas with higher temperatures and less ideal conditions, which helps diversify and stabilize coffee production amid environmental challenges. This adaptability positions Robusta as a valuable crop for the future of agriculture and food security.

    Health and Wellness Benefits

    Robusta isn’t just about bold flavor and high yields—it also carries potential health benefits. Its elevated caffeine and antioxidant levels may contribute to enhanced metabolism, improved focus, and greater alertness. Some cultures have even used it traditionally to alleviate ailments such as fatigue and headaches

    The Indian Connection

    India is one of the leading producers of Robusta coffee, with cultivation centered in the southern states. Indian Robusta is known for its depth, body, and ability to pair beautifully with milk and spices, making it a key ingredient in South Indian filter coffee. The rich soil and climate of these regions contribute to a distinctive quality that’s increasingly appreciated both locally and internationally.

    The Evolving Reputation of Robusta

    For years, Robusta was dismissed as inferior, mainly used for instant coffee or commercial blends. However, specialty coffee roasters and baristas are now revisiting this bean with fresh eyes. Through better cultivation methods and careful processing, high-quality Robusta beans are revealing complex flavors and offering a whole new tasting experience.

    As consumer palates evolve and the demand for sustainable crops grows, Robusta is stepping out of the shadows. It’s not just a filler anymore—it’s a bold, resilient, and increasingly celebrated player in the world of coffee.

    In a Nutshell: Robusta coffee is no longer just a backup to Arabica. With its strong flavor, robust nature, climate adaptability, and rising reputation, it is redefining what it means to enjoy a cup of coffee. Whether you’re a casual drinker or a connoisseur, Robusta is a bean worth paying attention to.

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Priyansh Srivastava
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Priyansh SrivastavaBeginner
Asked: 1 month agoIn: Mathematics

KINDLY GIVE ANSWER ALONG WITH PROOF

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  KINDLY GIVE ANSWER ALONG WITH PROOF

 

KINDLY GIVE ANSWER ALONG WITH PROOF

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  1. Pankaj Gupta
    Best Answer
    Pankaj Gupta Scholar
    Added an answer about 1 month ago

    Problem: There are 1000 doors, all initially closed. 1000 people walk by these doors. The first person opens every door. The second person toggles every second door (i.e., closes doors 2, 4, 6, etc.). The third person toggles every third door (i.e., doors 3, 6, 9, etc.), and so on. The 1000th personRead more

    Problem:
    There are 1000 doors, all initially closed. 1000 people walk by these doors. The first person opens every door. The second person toggles every second door (i.e., closes doors 2, 4, 6, etc.). The third person toggles every third door (i.e., doors 3, 6, 9, etc.), and so on. The 1000th person only toggles door 1000. After all the people have passed, how many doors remain open?

    Step 1: Understand the pattern
    Each person toggles the state of doors that are multiples of their own number. For example, person 12 will toggle doors 12, 24, 36, and so on. The state of each door will change every time it is toggled.

    Step 2: Think about how many times each door is toggled
    Take any door number, say door 6. It gets toggled by person 1 (since 1 divides 6), person 2 (2 divides 6), person 3 (3 divides 6), and person 6 (6 divides itself). In general, a door will be toggled once for each of its positive divisors.

    Step 3: Determine when a door ends up open
    Since all doors start closed, each toggle changes its state. So, if a door is toggled an even number of times, it will end up closed. If it is toggled an odd number of times, it will end up open.

    Step 4: Identify which door numbers are toggled an odd number of times
    From number theory, we know that most numbers have an even number of divisors because divisors usually come in pairs (like 2 and 3 for 6, since 2×3 = 6). However, perfect squares have an odd number of divisors. For example, 36 has divisors: 1, 2, 3, 4, 6, 9, 12, 18, and 36. Notice that 6×6 = 36, so the factor 6 appears only once, not in a pair. This gives it an odd number of total divisors.

    Therefore, only the doors with perfect square numbers will remain open at the end.

    Step 5: Count the perfect squares between 1 and 1000
    The perfect squares less than or equal to 1000 are:
    1² = 1,
    2² = 4,
    3² = 9,
    …
    31² = 961.

    So, there are 31 perfect squares between 1 and 1000.

    Final Answer:
    31 doors will remain open.

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Priyansh Srivastava
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Priyansh SrivastavaBeginner
Asked: 1 month agoIn: Mathematics

how to prove that for every non negative n , …

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how to prove that for every non negative n , sqrt(n) is either an integer or an irrational number .

how to prove that for every non negative n , sqrt(n) is either an integer or an irrational number .

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  1. AVG
    AVG Explorer
    Added an answer about 1 month ago

    For every non-negative integer \( n \), the square root \( \sqrt{n} \) is either an integer or an irrational number. Proof (by contradiction): Suppose \( \sqrt{n} \) is rational but **not** an integer. Then there exist integers \( a \) and \( b \), with \( \gcd(a, b) = 1 \) and \( b \ne 1 \), such tRead more

    For every non-negative integer \( n \), the square root \( \sqrt{n} \) is either an integer or an irrational number.

    Proof (by contradiction):

    Suppose \( \sqrt{n} \) is rational but **not** an integer.

    Then there exist integers \( a \) and \( b \), with \( \gcd(a, b) = 1 \) and \( b \ne 1 \), such that:
    \[
    \sqrt{n} = \frac{a}{b}
    \]

    Squaring both sides:
    \[
    n = \left( \frac{a}{b} \right)^2 = \frac{a^2}{b^2}
    \Rightarrow a^2 = n b^2
    \]

    This implies that \( b^2 \) divides \( a^2 \). But since \( \gcd(a, b) = 1 \), it follows that \( \gcd(a^2, b^2) = 1 \) as well. Hence, the only way \( b^2 \mid a^2 \) can be true is if \( b^2 = 1 \), which means:
    \[
    b = 1
    \Rightarrow \sqrt{n} = \frac{a}{1} = a \in \mathbb{Z}
    \]

    This contradicts our assumption that \( \sqrt{n} \) is rational **but not** an integer.

    Conclusion:
    If \( \sqrt{n} \) is rational, then it must be an integer.
    Therefore, if \( \sqrt{n} \) is not an integer, it must be irrational.

    \[
    \boxed{\text{For all } n \in \mathbb{N}_0,\ \sqrt{n} \in \mathbb{Z} \cup (\mathbb{R} \setminus \mathbb{Q})}
    \]

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Priyansh Srivastava
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Priyansh SrivastavaBeginner
Asked: 1 month agoIn: Mathematics

SHOW THAT :  2^(2N) – 3N -1  is divisible by …

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SHOW THAT :  2^(2N) – 3N -1  is divisible by 9  FOR ALL N>=1

SHOW THAT : 

2^(2N) – 3N -1  is divisible by 9 

FOR ALL N>=1

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  1. Harpreet
    Best Answer
    Harpreet Beginner
    Added an answer about 1 month ago

    Proof by Mathematical Induction: Base Case: Let \( n = 1 \) \[ 2^{2 \cdot 1} - 3 \cdot 1 - 1 = 2^2 - 3 - 1 = 4 - 3 - 1 = 0 \] \[ \Rightarrow 9 \mid 0 \quad \text{(True)} \] Inductive Hypothesis: Assume that for some \( n = k \), the expression is divisible by 9: \[ 2^{2k} - 3k - 1 \equiv 0 \pmod{9}Read more

    Proof by Mathematical Induction:

    Base Case: Let \( n = 1 \)

    \[
    2^{2 \cdot 1} – 3 \cdot 1 – 1 = 2^2 – 3 – 1 = 4 – 3 – 1 = 0
    \]

    \[
    \Rightarrow 9 \mid 0 \quad \text{(True)}
    \]

    Inductive Hypothesis: Assume that for some \( n = k \), the expression is divisible by 9:

    \[
    2^{2k} – 3k – 1 \equiv 0 \pmod{9}
    \]

    That is,

    \[
    2^{2k} – 3k – 1 = 9m \quad \text{for some integer } m
    \]

    To Prove: \( 2^{2(k+1)} – 3(k+1) – 1 \) is also divisible by 9.

    LHS:

    \[
    2^{2(k+1)} – 3(k+1) – 1 = 2^{2k + 2} – 3k – 3 – 1
    \]

    \[
    = 4 \cdot 2^{2k} – 3k – 4
    \]

    Now subtract the inductive hypothesis:

    \[
    [4 \cdot 2^{2k} – 3k – 4] – [2^{2k} – 3k – 1] = 3 \cdot 2^{2k} – 3
    \]

    \[
    = 3(2^{2k} – 1)
    \]

    Now, observe that \( 2^{2k} \equiv 1 \pmod{3} \), so \( 2^{2k} – 1 \equiv 0 \pmod{3} \)

    Hence, \( 3(2^{2k} – 1) \equiv 0 \pmod{9} \)

    Therefore, the expression for \( n = k+1 \) is also divisible by 9.

     

    Conclusion:

    \[
    \boxed{2^{2n} – 3n – 1 \text{ is divisible by } 9 \text{ for all } n \geq 1}
    \]

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Priyansh Srivastava
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Priyansh SrivastavaBeginner
Asked: 1 month agoIn: Mathematics

HOW TO PROVE THAT :  49+56(N^2 +1)  CAN NEVER BE …

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HOW TO PROVE THAT :  49+56(N^2 +1)  CAN NEVER BE A PERFECT SQUARE OF SOME INTEGER K  (WHERE N BELONGS TO THE SET OF NON NEGATIVE INTEGERS ) .  HINT : CONGRUENCE MODULO , PARITY 

HOW TO PROVE THAT : 

49+56(N^2 +1)  CAN NEVER BE A PERFECT SQUARE OF SOME INTEGER K  (WHERE N BELONGS TO THE SET OF NON NEGATIVE INTEGERS ) . 

HINT : CONGRUENCE MODULO , PARITY 

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  1. Pankaj Gupta
    Best Answer
    Pankaj Gupta Scholar
    Added an answer about 1 month ago

    Let’s simplify the expression: \[ 49 + 56(n^2 + 1) = 49 + 56n^2 + 56 = 56n^2 + 105 \] We need to prove that: \[ k^2 \ne 56n^2 + 105 \quad \text{for any integer } k \text{ and } n \in \mathbb{N}_0 \] Proof by Contradiction: Assume there exists some \( n \in \mathbb{N}_0 \) and \( k \in \mathbb{Z} \)Read more

    Let’s simplify the expression:

    \[
    49 + 56(n^2 + 1) = 49 + 56n^2 + 56 = 56n^2 + 105
    \]

    We need to prove that:

    \[
    k^2 \ne 56n^2 + 105 \quad \text{for any integer } k \text{ and } n \in \mathbb{N}_0
    \]

    Proof by Contradiction:

    Assume there exists some \( n \in \mathbb{N}_0 \) and \( k \in \mathbb{Z} \) such that:

    \[
    k^2 = 56n^2 + 105
    \]

    Rewriting:

    \[
    k^2 – 56n^2 = 105
    \]

    This is a Diophantine equation of the form:

    \[
    k^2 – 56n^2 = 105
    \]

    It resembles a generalized Pell’s equation, but unlike standard Pell’s equations, this has a non-zero right-hand side.

    To find integer solutions, test small values of \( n \):

    – \( n = 0 \Rightarrow k^2 = 105 \) → not a perfect square
    – \( n = 1 \Rightarrow k^2 = 56 + 105 = 161 \) → not a perfect square
    – \( n = 2 \Rightarrow k^2 = 224 + 105 = 329 \) → not a perfect square
    – \( n = 3 \Rightarrow k^2 = 504 + 105 = 609 \) → not a perfect square
    – \( n = 4 \Rightarrow k^2 = 896 + 105 = 1001 \) → not a perfect square
    – \( n = 5 \Rightarrow k^2 = 1400 + 105 = 1505 \) → not a perfect square
    – \( n = 6 \Rightarrow k^2 = 2016 + 105 = 2121 \) → not a perfect square

    And so on. No value of \( k^2 = 56n^2 + 105 \) becomes a perfect square for any non-negative integer \( n \).

    Also note:
    For \( k^2 \equiv 56n^2 + 105 \pmod{8} \), since:

    \[
    56n^2 \equiv 0 \pmod{8}, \quad \Rightarrow k^2 \equiv 105 \equiv 1 \pmod{8}
    \]

    Only \( k \equiv 1, 3, 5, 7 \pmod{8} \) will work. However, checking modulo 7:

    \[
    56n^2 + 105 \equiv 0n^2 + 0 = 0 \pmod{7}
    \Rightarrow k^2 \equiv 0 \pmod{7}
    \Rightarrow k \equiv 0 \pmod{7}
    \]

    So \( k = 7m \), and we get:

    \[
    (7m)^2 = 56n^2 + 105 \Rightarrow 49m^2 = 56n^2 + 105
    \Rightarrow 7m^2 = 8n^2 + 15
    \]

    Now check modulo 7:

    \[
    8n^2 + 15 \equiv m^2 \pmod{7}
    \Rightarrow (8n^2 + 15) \mod 7
    \]

    But trying all \( n = 0 \) to \( 6 \), none of the RHS becomes a multiple of 7 ⇒ contradiction.

    Conclusion:

    \[
    \boxed{49 + 56(n^2 + 1) \text{ is never a perfect square for any } n \in \mathbb{N}_0}
    \]

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Pankaj Gupta

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    Which skill is needed in future??

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    What are classical languages in India?

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    Reference of Vattakirutal on Sangam Poem

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    Dhanyakataka, a Prominent Buddhist Center of the Mahasanghikas

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    Pankaj Gupta added an answer In Java, the substring(int beginIndex, int endIndex) method returns a… July 5, 2025 at 9:33 am
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    Pankaj Gupta added an answer Key Difference Term Whitespace Unicode Space Character Definition Any character… June 16, 2025 at 4:44 pm
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    Pankaj Gupta added an answer Primary amebic meningoencephalitis (PAM) is a rare, usually fatal brain… June 7, 2025 at 11:44 am
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    Pankaj Gupta added an answer The capital of the Chola Empire during its peak was… June 4, 2025 at 11:27 pm
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    Pankaj Gupta added an answer The Tao Te Ching, attributed to Laozi (Lao Tzu) and… June 4, 2025 at 11:22 pm
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