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Harpreet
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HarpreetBeginner
Asked: 9 minutes agoIn:
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In Java, consider the following code snippet:Scanner sc = new Scanner(System.in); System.out.print("Enter your age: "); int age = sc.nextInt(); System.out.print("Enter your full name: "); String name = sc.nextLine(); System.out.println("Age: " + age); System.out.println("Name: " + name);When ...Read more

In Java, consider the following code snippet:

Scanner sc = new Scanner(System.in);

System.out.print("Enter your age: ");
int age = sc.nextInt();

System.out.print("Enter your full name: ");
String name = sc.nextLine();

System.out.println("Age: " + age);
System.out.println("Name: " + name);

When the input is:

20
Rahul Sharma

The output is:

Age: 20
Name:

Explain why the nextLine() method appears to “skip” input in this case.

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javanextline()scanner
  1. Pankaj Gupta
    Pankaj Gupta Scholar

    The nextLine() method appears to skip input because after executing nextInt(), the newline character (\n) from pressing Enter is still left in the input buffer. When nextLine() is called immediately after, it reads this leftover newline character instead of waiting for new user input. As a result, iRead more

    The nextLine() method appears to skip input because after executing nextInt(), the newline character (\n) from pressing Enter is still left in the input buffer.

    When nextLine() is called immediately after, it reads this leftover newline character instead of waiting for new user input. As a result, it returns an empty string and seems to “skip” the input.

    To fix the issue, insert an extra sc.nextLine(); after nextInt() to consume the leftover newline character.

    Scanner sc = new Scanner(System.in);

    System.out.print(“Enter your age: “);
    int age = sc.nextInt();
    sc.nextLine(); // consume the leftover newline

    System.out.print(“Enter your full name: “);
    String name = sc.nextLine();

    System.out.println(“Age: ” + age);
    System.out.println(“Name: ” + name);

    Now, if the input is:

    20
    Rahul Sharma

    The output will be:

    Age: 20
    Name: Rahul Sharma

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Pankaj Gupta
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Pankaj GuptaScholar
Asked: 17 minutes agoIn:
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What is the difference between next() and nextLine()?

What is the difference between next() and nextLine()?

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javanext()nextline()
  1. Pankaj Gupta
    Pankaj Gupta Scholar

    1. next() Function: Reads the next token (word) from input. Delimiter: Stops reading when it encounters whitespace (space, tab, or newline). Ignores: Leading whitespace before the token. Use case: Good for reading single words. Example: Scanner sc = new Scanner(System.in); System.out.print("Enter yoRead more

    1. next()

    • Function: Reads the next token (word) from input.

    • Delimiter: Stops reading when it encounters whitespace (space, tab, or newline).

    • Ignores: Leading whitespace before the token.

    • Use case: Good for reading single words.

    Example:

    Scanner sc = new Scanner(System.in);
    System.out.print("Enter your name: ");
    String name = sc.next();
    System.out.println("You entered: " + name);

    Input:

    Rahul Sharma

    Output:

    You entered: Rahul

    👉 It only captures "Rahul" because next() stops at the first space.

    2. nextLine()

    • Function: Reads the entire line of input (until Enter/\n).

    • Delimiter: Stops only when the newline character is encountered.

    • Use case: Good for reading sentences or full lines with spaces.

    Example:

    Scanner sc = new Scanner(System.in);
    System.out.print("Enter your full name: ");
    String name = sc.nextLine();
    System.out.println("You entered: " + name);

    Input:

    Rahul Sharma

    Output:

    You entered: Rahul Sharma

    👉 Here it captures the whole line, including spaces.

    ⚡ Key Differences Table

    Featurenext()nextLine()
    Reads up toWhitespace (space, tab, newline)End of line (\n)
    Can read spaces?❌ No (stops at space)✅ Yes (includes spaces)
    Best forSingle words/tokensFull sentences / whole line
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